current location:Mathematical operation >
History of Inequality Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 inequalities
[ 1/1Inequality]
Assignment:Find the solution set of inequality (0.1*0.1*q*q)/(1+sqrt(1+0.1*0.1*q*q))^2 >0.9 .
Question type: Inequality
Solution:
The inequality can be reduced to 1 inequality:
( 0.1 * 0.1 * q * q ) / ( 1 + sqrt ( 1 + 0.1 * 0.1 * q * q ) ) ^ 2 >0.9 (1)
From the definition field of √
1 + 0.1 * 0.1 * x * x ≥ 0 (2 )
From the definition field of divisor
1 + sqrt ( 1 + 0.1 * 0.1 * x * x ) ≠ 0 (3 )
From inequality(1):
q < -√36000 或 q > √36000
From inequality(2):
q ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
From inequality(3):
q ∈ R (R为全体实数),即在实数范围内,不等式恒成立!
From inequalities (1) and (2)
q < -√36000 或 q > √36000 (4)
From inequalities (3) and (4)
q < -√36000 或 q > √36000 (5)
The final solution set is :
q < -√36000 或 q > √36000Your problem has not been solved here? Please take a look at the hot problems !