current location:Mathematical operation >
History of Inequality Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 inequalities
[ 1/1Inequality]
Assignment:Find the solution set of inequality ((-10117010*x)+204269700*(1-x))/(sqrt(204269700*x^2+518921850000*(1-x)^2)) ≤0((-10117010*x)+204269700*(1-x))/(sqrt(204269700*x^2+518921850000*(1-x)^2)) = 0 .
Question type: Inequality
Solution:
The inequality can be reduced to 1 inequality:
( ( -10117010 * x ) + 204269700 * ( 1 - x ) ) / ( sqrt ( 204269700 * x ^ 2 + 518921850000 * ( 1 - x ) ^ 2 ) ) ≤0 * ( ( -10117010 * x ) + 204269700 * ( 1 - x ) ) / ( sqrt ( 204269700 * x ^ 2 + 518921850000 * ( 1 - x ) ^ 2 ) ) 0 (1)
From the definition field of √
204269700 * x ^ 2 + 518921850000 * ( 1 - x ) ^ 2 ≥ 0 (2 )
From the definition field of divisor
sqrt ( 204269700 * x ^ 2 + 518921850000 * ( 1 - x ) ^ 2 ) ≠ 0 (3 )
From the definition field of √
204269700 * x ^ 2 + 518921850000 * ( 1 - x ) ^ 2 ≥ 0 (4 )
From the definition field of divisor
sqrt ( 204269700 * x ^ 2 + 518921850000 * ( 1 - x ) ^ 2 ) ≠ 0 (5 )
From inequality(1):
x ≥ 0.95281
From inequality(2):
x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
From inequality(3):
x ∈ R (R为全体实数),即在实数范围内,不等式恒成立!
From inequality(4):
x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
From inequality(5):
x ∈ R (R为全体实数),即在实数范围内,不等式恒成立!
From inequalities (1) and (2)
x ≥ 0.95281 (6)
From inequalities (3) and (6)
x ≥ 0.95281 (7)
From inequalities (4) and (7)
x ≥ 0.95281 (8)
From inequalities (5) and (8)
x ≥ 0.95281 (9)
The final solution set is :
x ≥ 0.95281Your problem has not been solved here? Please take a look at the hot problems !