Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality (x∧2+2x-3)/(x∧2+x+2020) <0 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         ( x ^ 2 + 2 * x - 3 ) / ( x ^ 2 + x + 2020 ) <0         (1)
        From the definition field of divisor
         x ^ 2 + x + 2020 ≠ 0        (2 )

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    From inequality(1)：
         -3 < x < 1
    From inequality(2)：
         x ∈ R （R为全体实数），即在实数范围内，不等式恒成立！

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    From inequalities (1) and (2)
         -3 < x < 1     (3)

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    The final solution set is :
         -3 < x < 1

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