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Assignment:Find the solution set of inequality (60/x+20)+(40/x-20) <= 4 .
Question type: Inequality
Solution:
The inequality can be reduced to 1 inequality:
( 60 / x + 20 ) + ( 40 / x - 20 ) <= 4 (1)
From the definition field of divisor
x ≠ 0 (2 )
From the definition field of divisor
x ≠ 0 (3 )
From inequality(1):
x ≤ 0 或 x ≥ 25
From inequality(2):
x < 0 或 x > 0
From inequality(3):
x < 0 或 x > 0
From inequalities (1) and (2)
x < 0 或 x ≥ 25 (4)
From inequalities (3) and (4)
x < 0 或 x ≥ 25 (5)
The final solution set is :
x < 0 或 x ≥ 25Your problem has not been solved here? Please take a look at the hot problems !