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current location:Mathematical operation > History of Inequality Computation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality -sinx+ln((x^2+1)^0.5+x)+x-sin(3-2x)+ln(((3-2x)^2+1)^0.5+(3-2x))+3-2x <0 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality:
        -sin x + ln ( ( x ^ 2 + 1 ) ^ 0.5 + x ) + x - sin ( 3 - 2 * x ) + ln ( ( ( 3 - 2 * x ) ^ 2 + 1 ) ^ 0.5 + ( 3 - 2 * x ) ) + 3 - 2 * x <0         (1)
        From the definition field of ln
         ( x ^ 2 + 1 ) ^ 0.5 + x > 0        (2 )
        From the definition field of ln
         ( ( 3 - 2 * x ) ^ 2 + 1 ) ^ 0.5 + ( 3 - 2 * x ) > 0        (3 )

    From inequality(1):
         x > 3
    From inequality(2):
         x < -9411.73642 或  x > -9411.73642
    From inequality(3):
         x < 7014.24576 或  x > 7014.24576

    From inequalities (1) and (2)
         x > 3    (4)
    From inequalities (3) and (4)
         3 < x < 7014.24576 或  x > 7014.24576    (5)

    The final solution set is :

         3 < x < 7014.24576 或  x > 7014.24576




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