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current location:Mathematical operation > History of Inequality Computation > Answer
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           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (1050×12-70%×60X×7.2%)÷(30%×60X+2%×60X) = 3.8% .
    Question type: Equation
    Solution:Original question:
     (1050 × 12
70
100
× 60 X ×
36
500
) ÷ (
30
100
× 60 X +
2
100
× 60 X ) =
19
500
     Multiply both sides of the equation by:(
30
100
× 60 X +
2
100
× 60 X )
     (1050 × 12
70
100
× 60 X ×
36
500
) =
19
500
(
30
100
× 60 X +
2
100
× 60 X )
    Remove a bracket on the left of the equation::
     1050 × 12
70
100
× 60 X ×
36
500
=
19
500
(
30
100
× 60 X +
2
100
× 60 X )
    Remove a bracket on the right of the equation::
     1050 × 12
70
100
× 60 X ×
36
500
=
19
500
×
30
100
× 60 X +
19
500
×
2
100
× 60 X
    The equation is reduced to :
     12600
378
125
X =
171
250
X +
57
1250
X
    The equation is reduced to :
     12600
378
125
X =
456
625
X

    Transposition :
      -
378
125
X
456
625
X = - 12600

    Combine the items on the left of the equation:
      -
2346
625
X = - 12600

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     12600 =
2346
625
X

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
2346
625
X = 12600

    The coefficient of the unknown number is reduced to 1 :
      X = 12600 ÷
2346
625
        = 12600 ×
625
2346
        = 2100 ×
625
391

    We obtained :
      X =
1312500
391
    This is the solution of the equation.

    Convert the result to decimal form :
      X = 3356.777494




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