Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality (-16x/(4xx+25)+56x/(49xx+36))^2+(2+(16xx/60)/(4xx+25)+(196xx+96)/(49xx+36))^2-2(10+(80xx+300)/(4xx+25)+(980xx+480)/(49xx+36)) <0 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         ( -16 * x / ( 4 * x * x + 25 ) + 56 * x / ( 49 * x * x + 36 ) ) ^ 2 + ( 2 + ( 16 * x * x / 60 ) / ( 4 * x * x + 25 ) + ( 196 * x * x + 96 ) / ( 49 * x * x + 36 ) ) ^ 2 - 2 * ( 10 + ( 80 * x * x + 300 ) / ( 4 * x * x + 25 ) + ( 980 * x * x + 480 ) / ( 49 * x * x + 36 ) ) <0         (1)
        From the definition field of divisor
         4 * x * x + 25 ≠ 0        (2 )
        From the definition field of divisor
         49 * x * x + 36 ≠ 0        (3 )
        From the definition field of divisor
         4 * x * x + 25 ≠ 0        (4 )
        From the definition field of divisor
         49 * x * x + 36 ≠ 0        (5 )
        From the definition field of divisor
         4 * x * x + 25 ≠ 0        (6 )
        From the definition field of divisor
         49 * x * x + 36 ≠ 0        (7 )

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    From inequality(1)：
         x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
    From inequality(2)：
         x ∈ R （R为全体实数），即在实数范围内，不等式恒成立！
    From inequality(3)：
         x ∈ R （R为全体实数），即在实数范围内，不等式恒成立！
    From inequality(4)：
         x ∈ R （R为全体实数），即在实数范围内，不等式恒成立！
    From inequality(5)：
         x ∈ R （R为全体实数），即在实数范围内，不等式恒成立！
    From inequality(6)：
         x ∈ R （R为全体实数），即在实数范围内，不等式恒成立！
    From inequality(7)：
         x ∈ R （R为全体实数），即在实数范围内，不等式恒成立！

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    From inequalities (1) and (2)
         x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!    (8)
    From inequalities (3) and (8)
         x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!    (9)
    From inequalities (4) and (9)
         x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!    (10)
    From inequalities (5) and (10)
         x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!    (11)
    From inequalities (6) and (11)
         x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!    (12)
    From inequalities (7) and (12)
         x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!    (13)

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    The final solution set is :
         x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!

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