Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality [2/(x-0.2)]+[2/(x-0.04)]+[2/(x-0.12)] ≤[x/(0.1x-0.02)] .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         ( 2 / ( x - 0.2 ) ) + ( 2 / ( x - 0.04 ) ) + ( 2 / ( x - 0.12 ) ) ≤ ( x / ( 0.1 * x - 0.02 ) )         (1)
        From the definition field of divisor
         x - 0.2 ≠ 0        (2 )
        From the definition field of divisor
         x - 0.04 ≠ 0        (3 )
        From the definition field of divisor
         x - 0.12 ≠ 0        (4 )
        From the definition field of divisor
         0.1 * x - 0.02 ≠ 0        (5 )

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    From inequality(1)：
         x ≤ 0.12 或  x ≥ 0.483961
    From inequality(2)：
         x < 1/5 或  x ＞ 1/5
    From inequality(3)：
         x < 1/25 或  x ＞ 1/25
    From inequality(4)：
         x < 3/25 或  x ＞ 3/25
    From inequality(5)：
         x < 1/5 或  x ＞ 1/5

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    From inequalities (1) and (2)
         x ≤ 0.12 或  x ≥ 0.483961    (6)
    From inequalities (3) and (6)
         x < 1/25 或  1/25 < x ≤ 0.12 或  x ≥ 0.483961    (7)
    From inequalities (4) and (7)
         x < 1/25 或  1/25 < x < 3/25 或  x ≥ 0.483961    (8)
    From inequalities (5) and (8)
         x < 1/25 或  1/25 < x < 3/25 或  x ≥ 0.483961    (9)

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    The final solution set is :
         x < 1/25 或  1/25 < x < 3/25 或  x ≥ 0.483961

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