Mathematics
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current location:Mathematical operation > History of Inequality Computation > Answer
    Overview: 2 questions will be solved this time.Among them
           ☆2 inequalities

[ 1/2Inequality]
    Assignment:Find the solution set of inequality x1+x2+x3+x4 <= 11000 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality:
         x * 1 + x * 2 + x * 3 + x * 4 <= 11000         (1)

    From inequality(1):
         x ≤ 1100

    The final solution set is :

         x ≤ 1100

[ 2/2Inequality]
    Assignment:Find the solution set of inequality x1/(x1+x2+x3+x4) <= 0.65 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality:
         x * 1 / ( x * 1 + x * 2 + x * 3 + x * 4 ) <= 0.65         (1)
        From the definition field of divisor
         x * 1 + x * 2 + x * 3 + x * 4 ≠ 0        (2 )

    From inequality(1):
         x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
    From inequality(2):
         x < 0 或  x > 0

    From inequalities (1) and (2)
         x < 0 或  x > 0    (3)

    The final solution set is :

         x < 0 或  x > 0




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