总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×((140.625+122.5+75.98)/2558.1×10^3+20)/(700-35))×((9900/700))^2×1 的值.
题型:数学计算
解:
1+1/(1300×((140.625+122.5+75.98)/2558.1×10^3+20)/(700-35))×((9900/700))^2×1
=1+1/(1300×(339.105/2558.1×10^3+20)/(700-35))×((9900/700))^2×1
=1+1/(1300×152.561/(700-35))×((9900/700))^2×1
=1+1/(1300×152.561/665)×((9900/700))^2×1
=1+1/298.239549×((9900/700))^2×1
=1+1/298.239549×(14.142857)^2×1
=1+1/298.239549×14.142857^2×1
=1+1/298.239549×200.02040412244898×1
=1+0.003353×200.02040412244898×1
=1+0.670668×1
=1+0.670668
=1.670668 答案:1+1/(1300×((140.625+122.5+75.98)/2558.1×10^3+20)/(700-35))×((9900/700))^2×1=1.670668你的问题在这里没有得到解决?请到 热门难题 里面看看吧!