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☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×((164.06+125+54.486)/1816.2×10^3+23.3)/(700-35))*((10000/700))^2 的值.
题型:数学计算
解:
1+1/(1300×((164.06+125+54.486)/1816.2×10^3+23.3)/(700-35))*((10000/700))^2
=1+1/(1300×(343.546/1816.2×10^3+23.3)/(700-35))*((10000/700))^2
=1+1/(1300×212.456/(700-35))*((10000/700))^2
=1+1/(1300×212.456/665)*((10000/700))^2
=1+1/415.327519*((10000/700))^2
=1+1/415.327519*(14.285714)^2
=1+1/415.327519*14.285714^2
=1+1/415.327519*204.081624489796013
=1+0.002408*204.081624489796013
=1+0.491429
=1.491429 答案:1+1/(1300×((164.06+125+54.486)/1816.2×10^3+23.3)/(700-35))*((10000/700))^2=1.491429你的问题在这里没有得到解决?请到 热门难题 里面看看吧!