Mathematics
         
语言:中文    Language:English
On line solution of multivariate equations:
    First set the elements of the equation (i.e. the number of unknowns), then click the "Next" button to enter the coefficients of each element of the equation set, and click the "Next" button to obtain the solution of the equation set.
    Note that the coefficients of each element of the equation system can only be numbers, not algebraic expressions (including mathematical functions).
    Current location:Equations > Multivariate equations > Answer
detailed information:
The input equation set is:
 5A + 
5
2
B + 
15
8
C + 
63
40
D + 
63
40
E = 
343
40
    (1)
 
5
2
A + 
3
2
B + 
3
2
C + 
3
2
D + 
3
2
E = 
11
2
    (2)
 
3
2
A + 
3
2
B + 
3
2
C + 
3
2
D + 
3
2
E = 
9
2
    (3)
 
3
2
A + 
3
2
B + 
3
2
C + 
3
2
D + 
3
2
E = 
7
2
    (4)
 
3
2
A + 
3
2
B + 
3
2
C + 
3
2
D + 
3
2
E = 
7
2
    (5)
Question solving process:

Divide the two sides of equation (1) by 2, the equation can be obtained:
         
5
2
A + 
5
4
B + 
15
16
C + 
63
80
D + 
63
80
E = 
343
80
    (6)
, then subtract both sides of equation (6) from both sides of equation (2), the equations are reduced to:
 5A + 
5
2
B + 
15
8
C + 
63
40
D + 
63
40
E = 
343
40
    (1)
 
1
4
B + 
9
16
C + 
57
80
D + 
57
80
E = 
97
80
    (2)
 
3
2
A + 
3
2
B + 
3
2
C + 
3
2
D + 
3
2
E = 
9
2
    (3)
 
3
2
A + 
3
2
B + 
3
2
C + 
3
2
D + 
3
2
E = 
7
2
    (4)
 
3
2
A + 
3
2
B + 
3
2
C + 
3
2
D + 
3
2
E = 
7
2
    (5)

Multiply both sides of equation (1) by 3
Divide the two sides of equation (1) by 10, the equation can be obtained:
         
3
2
A + 
3
4
B + 
9
16
C + 
189
400
D + 
189
400
E = 
1029
400
    (7)
, then subtract both sides of equation (7) from both sides of equation (3), the equations are reduced to:
 5A + 
5
2
B + 
15
8
C + 
63
40
D + 
63
40
E = 
343
40
    (1)
 
1
4
B + 
9
16
C + 
57
80
D + 
57
80
E = 
97
80
    (2)
 
3
4
B + 
15
16
C + 
411
400
D + 
411
400
E = 
771
400
    (3)
 
3
2
A + 
3
2
B + 
3
2
C + 
3
2
D + 
3
2
E = 
7
2
    (4)
 
3
2
A + 
3
2
B + 
3
2
C + 
3
2
D + 
3
2
E = 
7
2
    (5)

Multiply both sides of equation (1) by 3
Divide the two sides of equation (1) by 10, the equation can be obtained:
         
3
2
A + 
3
4
B + 
9
16
C + 
189
400
D + 
189
400
E = 
1029
400
    (8)
, then subtract both sides of equation (8) from both sides of equation (4), the equations are reduced to:
 5A + 
5
2
B + 
15
8
C + 
63
40
D + 
63
40
E = 
343
40
    (1)
 
1
4
B + 
9
16
C + 
57
80
D + 
57
80
E = 
97
80
    (2)
 
3
4
B + 
15
16
C + 
411
400
D + 
411
400
E = 
771
400
    (3)
 
3
4
B + 
15
16
C + 
411
400
D + 
411
400
E = 
371
400
    (4)
 
3
2
A + 
3
2
B + 
3
2
C + 
3
2
D + 
3
2
E = 
7
2
    (5)

Multiply both sides of equation (1) by 3
Divide the two sides of equation (1) by 10, the equation can be obtained:
         
3
2
A + 
3
4
B + 
9
16
C + 
189
400
D + 
189
400
E = 
1029
400
    (9)
, then subtract both sides of equation (9) from both sides of equation (5), the equations are reduced to:
 5A + 
5
2
B + 
15
8
C + 
63
40
D + 
63
40
E = 
343
40
    (1)
 
1
4
B + 
9
16
C + 
57
80
D + 
57
80
E = 
97
80
    (2)
 
3
4
B + 
15
16
C + 
411
400
D + 
411
400
E = 
771
400
    (3)
 
3
4
B + 
15
16
C + 
411
400
D + 
411
400
E = 
371
400
    (4)
 
3
4
B + 
15
16
C + 
411
400
D + 
411
400
E = 
371
400
    (5)

Multiply both sides of equation (2) by 3, the equation can be obtained:
         
3
4
B + 
27
16
C + 
171
80
D + 
171
80
E = 
291
80
    (10)
, then subtract both sides of equation (10) from both sides of equation (3), the equations are reduced to:
 5A + 
5
2
B + 
15
8
C + 
63
40
D + 
63
40
E = 
343
40
    (1)
 
1
4
B + 
9
16
C + 
57
80
D + 
57
80
E = 
97
80
    (2)
3
4
C 
111
100
D 
111
100
E = 
171
100
    (3)
 
3
4
B + 
15
16
C + 
411
400
D + 
411
400
E = 
371
400
    (4)
 
3
4
B + 
15
16
C + 
411
400
D + 
411
400
E = 
371
400
    (5)

Multiply both sides of equation (2) by 3, the equation can be obtained:
         
3
4
B + 
27
16
C + 
171
80
D + 
171
80
E = 
291
80
    (11)
, then subtract both sides of equation (11) from both sides of equation (4), the equations are reduced to:
 5A + 
5
2
B + 
15
8
C + 
63
40
D + 
63
40
E = 
343
40
    (1)
 
1
4
B + 
9
16
C + 
57
80
D + 
57
80
E = 
97
80
    (2)
3
4
C 
111
100
D 
111
100
E = 
171
100
    (3)
3
4
C 
111
100
D 
111
100
E = 
271
100
    (4)
 
3
4
B + 
15
16
C + 
411
400
D + 
411
400
E = 
371
400
    (5)

Multiply both sides of equation (2) by 3, the equation can be obtained:
         
3
4
B + 
27
16
C + 
171
80
D + 
171
80
E = 
291
80
    (12)
, then subtract both sides of equation (12) from both sides of equation (5), the equations are reduced to:
 5A + 
5
2
B + 
15
8
C + 
63
40
D + 
63
40
E = 
343
40
    (1)
 
1
4
B + 
9
16
C + 
57
80
D + 
57
80
E = 
97
80
    (2)
3
4
C 
111
100
D 
111
100
E = 
171
100
    (3)
3
4
C 
111
100
D 
111
100
E = 
271
100
    (4)
3
4
C 
111
100
D 
111
100
E = 
271
100
    (5)

Subtract both sides of equation (3) from both sides of equation (4) ,the equations are reduced to:
 5A + 
5
2
B + 
15
8
C + 
63
40
D + 
63
40
E = 
343
40
    (1)
 
1
4
B + 
9
16
C + 
57
80
D + 
57
80
E = 
97
80
    (2)
3
4
C 
111
100
D 
111
100
E = 
171
100
    (3)
0 = -1    (4)
3
4
C 
111
100
D 
111
100
E = 
271
100
    (5)

由第(4)方程式可以看出,该方程组无解。

解方程组的详细方法请参阅:《多元一次方程组的解法》







  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。