detailed information: The input equation set is: Question solving process:
交After the exchange of equation (1) and equation (3), the equation system becomes:
Multiply both sides of equation (1) by 10, the equation can be obtained: , then add the two sides of equation (7) to both sides of equation (5), the equations are reduced to:
Multiply both sides of equation (2) by 10, the equation can be obtained: , then subtract both sides of equation (8) from both sides of equation (4), the equations are reduced to:
Multiply both sides of equation (2) by 20, the equation can be obtained: , then subtract both sides of equation (9) from both sides of equation (5), the equations are reduced to:
| | | | | | | -24 | C | + | | 20 | D | + | | 10 | F | = | | 20 | | (5) |
| |
交After the exchange of equation (3) and equation (4), the equation system becomes:
| | | | | | | -24 | C | + | | 20 | D | + | | 10 | F | = | | 20 | | (5) |
| |
Multiply both sides of equation (3) by 12 Divide the two sides of equation (3) by 5, the equation can be obtained: | -24 | C | + | | | 216 5 | D | | - | 24 5 | F | = | | -96 | (10) | , then subtract both sides of equation (10) from both sides of equation (5), the equations are reduced to:
Multiply both sides of equation (3) by 2 Divide the two sides of equation (3) by 5, the equation can be obtained: | -4 | C | + | | | 36 5 | D | | - | 4 5 | F | = | | -16 | (11) | , then add the two sides of equation (11) to both sides of equation (6), the equations are reduced to:
Multiply both sides of equation (4) by 116 Divide the two sides of equation (4) by 5, the equation can be obtained: | | | 116 5 | D | + | | | 116 5 | E | + | | | 116 5 | F | = | | 0 | (12) | , then add the two sides of equation (12) to both sides of equation (5), the equations are reduced to:
Multiply both sides of equation (4) by 76 Divide the two sides of equation (4) by 5, the equation can be obtained: | | | 76 5 | D | + | | | 76 5 | E | + | | | 76 5 | F | = | | 0 | (13) | , then subtract both sides of equation (13) from both sides of equation (6), the equations are reduced to:
Add both sides of equation (5) to both sides of equation (6) ,the equations are reduced to:
Multiply both sides of equation (6) by 19 Divide both sides of equation (6) by 11, get the equation:, then subtract both sides of equation (14) from both sides of equation (5), get the equation:
Divide both sides of equation (6) by 22, get the equation:, then subtract both sides of equation (15) from both sides of equation (4), get the equation:
Divide both sides of equation (6) by 11, get the equation:, then add the two sides of equation (16) to both sides of equation (3), get the equation:
Divide both sides of equation (6) by 22, get the equation:, then subtract both sides of equation (17) from both sides of equation (1), get the equation:
Multiply both sides of equation (5) by 5 Divide both sides of equation (5) by 116, get the equation:, then subtract both sides of equation (18) from both sides of equation (4), get the equation:
Multiply both sides of equation (4) by 18, get the equation:, then subtract both sides of equation (19) from both sides of equation (3), get the equation:
Add both sides of equation (4) to both sides of equation (2), get the equation:
Divide both sides of equation (3) by 10, get the equation:, then add the two sides of equation (20) to both sides of equation (2), get the equation:
Subtract both sides of equation (2) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |