detailed information: The input equation set is: Question solving process:
交After the exchange of equation (1) and equation (3), the equation system becomes:
Divide the two sides of equation (1) by 5, the equation can be obtained: | | A | + | | | 1 5 | B | + | | | 1 5 | C | + | | | 1 5 | D | = | | | 1 5 | (5) | , then subtract both sides of equation (5) from both sides of equation (4), the equations are reduced to:
| | | | | | | | 4 5 | B | + | | | 44 5 | C | + | | | 44 5 | D | = | | | 109 5 | | (4) |
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交After the exchange of equation (2) and equation (3), the equation system becomes:
| | | | | | | | 4 5 | B | + | | | 44 5 | C | + | | | 44 5 | D | = | | | 109 5 | | (4) |
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Multiply both sides of equation (2) by 4 Divide the two sides of equation (2) by 5, the equation can be obtained: , then subtract both sides of equation (6) from both sides of equation (4), the equations are reduced to:
交After the exchange of equation (3) and equation (4), the equation system becomes:
Multiply both sides of equation (4) by 56 Divide both sides of equation (4) by 5, get the equation:, then add the two sides of equation (7) to both sides of equation (3), get the equation:
Multiply both sides of equation (4) by 25, get the equation:, then subtract both sides of equation (8) from both sides of equation (2), get the equation:
Subtract both sides of equation (4) from both sides of equation (1), get the equation:
Multiply both sides of equation (3) by 5 Divide both sides of equation (3) by 44, get the equation:, then subtract both sides of equation (9) from both sides of equation (1), get the equation:
Subtract both sides of equation (2) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |