Mathematics
         
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    Current location:Mathematical operation > History of Mathematical Computation > Answer

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           ☆1 arithmetic calculations

[1/1 Formula]
    Work: Calculate the value of equation (230+50)×4+9×50×2+7×50×2+533.61+36+17.25+15.25+35 .
    Question type: Mathematical calculation
    Solution:
          (230+50)×4+9×50×2+7×50×2+533.61+36+17.25+15.25+35
        =280×4+9×50×2+7×50×2+533.61+36+17.25+15.25+35
        =1120+9×50×2+7×50×2+533.61+36+17.25+15.25+35
        =1120+450×2+7×50×2+533.61+36+17.25+15.25+35
        =1120+900+7×50×2+533.61+36+17.25+15.25+35
        =1120+900+350×2+533.61+36+17.25+15.25+35
        =1120+900+700+533.61+36+17.25+15.25+35
        =2020+700+533.61+36+17.25+15.25+35
        =2720+533.61+36+17.25+15.25+35
        =3253.61+36+17.25+15.25+35
        =3289.61+17.25+15.25+35
        =3306.86+15.25+35
        =3322.11+35
        =3357.11

    Answer:(230+50)×4+9×50×2+7×50×2+533.61+36+17.25+15.25+35=3357.11


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