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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation (x+3)(x+1）(x-3) = 0 .
Question type: Equation
Solution:Original question:
Remove the bracket on the left of the equation:
The equation is transformed into :
After the equation is converted into a general formula, it is converted into:
( x + 3 )( x + 1 )( x - 3 )=0
From
x + 3 = 0
x + 1 = 0
x - 3 = 0
it is concluded that:：
x1=-3
x2=-1
x3=3
There are 3 solution(s).
解程的详细方法请参阅：《方程的解法》
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation (x+3)(x+1）(x-3) = 0 .
Question type: Equation
Solution:Original question:
| ( | x | + | 3 | ) | ( | x | + | 1 | ) | ( | x | − | 3 | ) | = | 0 |
| Left side of the equation = | x | ( | x | + | 1 | ) | ( | x | − | 3 | ) | + | 3 | ( | x | + | 1 | ) | ( | x | − | 3 | ) |
| = | x | x | ( | x | − | 3 | ) | + | x | × | 1 | ( | x | − | 3 | ) | + | 3 | ( | x | + | 1 | ) | ( | x | − | 3 | ) |
| = | x | x | x | − | x | x | × | 3 | + | x | × | 1 | ( | x | − | 3 | ) | + | 3 | ( | x | + | 1 | ) | ( | x | − | 3 | ) |
| = | x | x | x | − | x | x | × | 3 | + | x | × | 1 | x | − | x | × | 1 | × | 3 |
| = | x | x | x | − | x | x | × | 3 | + | x | × | 1 | x | − | x | × | 3 | + | 3 |
| = | x | x | x | − | x | x | × | 3 | + | x | × | 1 | x | − | 3 | x | + | 3 |
| = | x | x | x | − | x | x | × | 3 | + | x | × | 1 | x | − | 3 | x | + | 3 |
| = | x | x | x | − | x | x | × | 3 | + | x | × | 1 | x | − | 3 | x | + | 3 |
| = | x | x | x | − | x | x | × | 3 | + | x | × | 1 | x | − | 3 | x | + | 3 |
| = | x | x | x | − | x | x | × | 3 | + | x | × | 1 | x | − | 12 | x | + | 3 |
| = | x | x | x | − | x | x | × | 3 | + | x | × | 1 | x | − | 12 | x | + | 3 |
| = | x | x | x | − | x | x | × | 3 | + | x | × | 1 | x | − | 12 | x | + | 3 |
| = | x | x | x | − | x | x | × | 3 | + | x | × | 1 | x | − | 9 | x | + | 3 |
| x | x | x | − | x | x | × | 3 | + | x | × | 1 | x | − | 9 | x | + | 3 | = | 0 |
After the equation is converted into a general formula, it is converted into:
( x + 3 )( x + 1 )( x - 3 )=0
From
x + 3 = 0
x + 1 = 0
x - 3 = 0
it is concluded that:：
x1=-3
x2=-1
x3=3
There are 3 solution(s).
解程的详细方法请参阅：《方程的解法》