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[1/1 Formula]
    Work: Calculate the value of equation 2/sqrt(3)*500*ln1-320+320*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1) .
    Question type: Mathematical calculation
    Solution:
          2/sqrt(3)*500*ln1-320+320*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)
        =2/sqrt3*500*ln1-320+320*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)
        =2/sqrt3*500*ln1-320+320*0.05^2/0.0075*(0.1^2/0.05^2-1)
        =2/sqrt3*500*ln1-320+320*0.05^2/0.0075*3
        =2/1.732051*500*ln1-320+320*0.05^2/0.0075*3
        =2/1.732051*500*0-320+320*0.05^2/0.0075*3
        =2/1.732051*500*0-320+320*0.0025/0.0075*3
        =1.1547*500*0-320+320*0.0025/0.0075*3
        =577.35*0-320+320*0.0025/0.0075*3
        =0-320+320*0.0025/0.0075*3
        =0-320+0.8/0.0075*3
        =0-320+106.666667*3
        =0-320+320.000001
        =-320+320.000001
        =0.000001

    Answer:2/sqrt(3)*500*ln1-320+320*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)=0.000001


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