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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1/d+1/(d+25)+1/(d+8) = 1/(d+71) .
    Question type: Equation
    Solution:Original question:
     1 ÷ d + 1 ÷ ( d + 25) + 1 ÷ ( d + 8) = 1 ÷ ( d + 71)
     Multiply both sides of the equation by: d  ,  ( d + 71)
     1( d + 71) + 1 ÷ ( d + 25) × d ( d + 71) + 1 ÷ ( d + 8) × d ( d + 71) = 1 d
    Remove a bracket on the left of the equation::
     1 d + 1 × 71 + 1 ÷ ( d + 25) × d ( d + 71) + 1 ÷ ( d + 8) × d ( d + 71) = 1 d
    The equation is reduced to :
     1 d + 71 + 1 ÷ ( d + 25) × d ( d + 71) + 1 ÷ ( d + 8) × d ( d + 71) = 1 d
     Multiply both sides of the equation by:( d + 25)
     1 d ( d + 25) + 71( d + 25) + 1 d ( d + 71) + 1 ÷ ( d + 8) × d ( d + 71) = 1 d ( d + 25)
    Remove a bracket on the left of the equation:
     1 d d + 1 d × 25 + 71( d + 25) + 1 d ( d + 71) + 1 = 1 d ( d + 25)
    Remove a bracket on the right of the equation::
     1 d d + 1 d × 25 + 71( d + 25) + 1 d ( d + 71) + 1 = 1 d d + 1 d × 25
    The equation is reduced to :
     1 d d + 25 d + 71( d + 25) + 1 d ( d + 71) + 1 ÷ ( d + 8) = 1 d d + 25 d
     Multiply both sides of the equation by:( d + 8)
     1 d d ( d + 8) + 25 d ( d + 8) + 71( d + 25)( d + 8) + 1 d = 1 d d ( d + 8) + 25 d ( d + 8)
    Remove a bracket on the left of the equation:
     1 d d d + 1 d d × 8 + 25 d ( d + 8) + 71 = 1 d d ( d + 8) + 25 d ( d + 8)
    Remove a bracket on the right of the equation::
     1 d d d + 1 d d × 8 + 25 d ( d + 8) + 71 = 1 d d d + 1 d d × 8 + 25 d ( d + 8)
    The equation is reduced to :
     1 d d d + 8 d d + 25 d ( d + 8) + 71( d + 25) = 1 d d d + 8 d d + 25 d ( d + 8)
    Remove a bracket on the left of the equation:
     1 d d d + 8 d d + 25 d d + 25 d = 1 d d d + 8 d d + 25 d ( d + 8)
    Remove a bracket on the right of the equation::
     1 d d d + 8 d d + 25 d d + 25 d = 1 d d d + 8 d d + 25 d d + 25 d
    The equation is reduced to :
     1 d d d + 8 d d + 25 d d + 200 d = 1 d d d + 8 d d + 25 d d + 200 d
    Remove a bracket on the left of the equation:
     1 d d d + 8 d d + 25 d d + 200 d = 1 d d d + 8 d d + 25 d d + 200 d
    The equation is reduced to :
     1 d d d + 8 d d + 25 d d + 200 d = 1 d d d + 8 d d + 25 d d + 200 d
    Remove a bracket on the left of the equation:
     1 d d d + 8 d d + 25 d d + 200 d = 1 d d d + 8 d d + 25 d d + 200 d
    The equation is reduced to :
     1 d d d + 8 d d + 25 d d + 200 d = 1 d d d + 8 d d + 25 d d + 200 d
    The equation is reduced to :
     1 d d d + 8 d d + 25 d d + 768 d = 1 d d d + 8 d d + 25 d d + 200 d
    Remove a bracket on the left of the equation:
     1 d d d + 8 d d + 25 d d + 768 d = 1 d d d + 8 d d + 25 d d + 200 d
    The equation is reduced to :
     1 d d d + 8 d d + 25 d d + 768 d = 1 d d d + 8 d d + 25 d d + 200 d

    The solution of the equation:
        d1≈-100.358670 , keep 6 decimal places
        d2≈-18.897683 , keep 6 decimal places
        d3≈-3.743647 , keep 6 decimal places
    
    There are 3 solution(s).


解程的详细方法请参阅:《方程的解法》



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