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    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (2d+5)(d+7)(d+1)(d+2)(d+3)8 = 0 .
    Question type: Equation
    Solution:Original question:
     (2 d + 5)( d + 7)( d + 1)( d + 2)( d + 3) × 8 = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = 2 d ( d + 7)( d + 1)( d + 2)( d + 3) × 8 + 5( d + 7)( d + 1)( d + 2)( d + 3)
                                             = 16 d ( d + 7)( d + 1)( d + 2)( d + 3) + 40( d + 7)( d + 1)( d + 2)( d + 3)
                                             = 16 d d ( d + 1)( d + 2)( d + 3) + 16 d × 7( d + 1)( d + 2)( d + 3)
                                             = 16 d d ( d + 1)( d + 2)( d + 3) + 112 d ( d + 1)( d + 2)( d + 3) + 40
                                             = 16 d d d ( d + 2)( d + 3) + 16 d d × 1( d + 2)( d + 3)
                                             = 16 d d d ( d + 2)( d + 3) + 16 d d ( d + 2)( d + 3) + 112
                                             = 16 d d d d ( d + 3) + 16 d d d × 2( d + 3)
                                             = 16 d d d d ( d + 3) + 32 d d d ( d + 3) + 16
                                             = 16 d d d d d + 16 d d d d × 3
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32
                                             = 16 d d d d d + 48 d d d d + 32

    After the equation is converted into a general formula, it is converted into:
    ( d + 7 )( d + 3 )( 2d + 5 )( d + 2 )( d + 1 )=0
    From
        d + 7 = 0
        d + 3 = 0
        2d + 5 = 0
        d + 2 = 0
        d + 1 = 0

    it is concluded that::
        d1=-7
        d2=-3
        d3=-
5
2
        d4=-2
        d5=-1
    
    There are 5 solution(s).


解程的详细方法请参阅:《方程的解法》



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