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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 0.002*0.75/(1+x)+0.005*0.75/(1+x)/(1+x)+0.01*0.75/(1+x)/(1+x)/(1+x) = 1 .
    Question type: Equation
    Solution:Original question:
     
1
500
×
3
4
÷ (1 + x ) +
1
200
×
3
4
÷ (1 + x ) ÷ (1 + x ) +
1
100
×
3
4
÷ (1 + x ) ÷ (1 + x ) ÷ (1 + x ) = 1
     Multiply both sides of the equation by:(1 + x )
     
1
500
×
3
4
+
1
200
×
3
4
÷ (1 + x ) +
1
100
×
3
4
÷ (1 + x ) ÷ (1 + x ) = 1(1 + x )
    Remove a bracket on the right of the equation::
     
1
500
×
3
4
+
1
200
×
3
4
÷ (1 + x ) +
1
100
×
3
4
÷ (1 + x ) ÷ (1 + x ) = 1 × 1 + 1 x
    The equation is reduced to :
     
3
2000
+
3
800
÷ (1 + x ) +
3
400
÷ (1 + x ) ÷ (1 + x ) = 1 + 1 x
     Multiply both sides of the equation by:(1 + x )
     
3
2000
(1 + x ) +
3
800
+
3
400
÷ (1 + x ) = 1(1 + x ) + 1 x (1 + x )
    Remove a bracket on the left of the equation:
     
3
2000
× 1 +
3
2000
x +
3
800
+
3
400
÷ (1 + x ) = 1(1 + x ) + 1 x (1 + x )
    Remove a bracket on the right of the equation::
     
3
2000
× 1 +
3
2000
x +
3
800
+
3
400
÷ (1 + x ) = 1 × 1 + 1 x + 1 x (1 + x )
    The equation is reduced to :
     
3
2000
+
3
2000
x +
3
800
+
3
400
÷ (1 + x ) = 1 + 1 x + 1 x (1 + x )
    The equation is reduced to :
     
21
4000
+
3
2000
x +
3
400
÷ (1 + x ) = 1 + 1 x + 1 x (1 + x )
     Multiply both sides of the equation by:(1 + x )
     
21
4000
(1 + x ) +
3
2000
x (1 + x ) +
3
400
= 1(1 + x ) + 1 x (1 + x ) + 1 x (1 + x )(1 + x )
    Remove a bracket on the left of the equation:
     
21
4000
× 1 +
21
4000
x +
3
2000
x (1 + x ) +
3
400
= 1(1 + x ) + 1 x (1 + x ) + 1 x (1 + x )(1 + x )
    Remove a bracket on the right of the equation::
     
21
4000
× 1 +
21
4000
x +
3
2000
x (1 + x ) +
3
400
= 1 × 1 + 1 x + 1 x (1 + x ) + 1 x (1 + x )(1 + x )
    The equation is reduced to :
     
21
4000
+
21
4000
x +
3
2000
x (1 + x ) +
3
400
= 1 + 1 x + 1 x (1 + x ) + 1 x (1 + x )(1 + x )
    The equation is reduced to :
     
51
4000
+
21
4000
x +
3
2000
x (1 + x ) = 1 + 1 x + 1 x (1 + x ) + 1 x (1 + x )(1 + x )
    Remove a bracket on the left of the equation:
     
51
4000
+
21
4000
x +
3
2000
x × 1 +
3
2000
x x = 1 + 1 x + 1 x (1 + x ) + 1 x (1 + x )(1 + x )
    Remove a bracket on the right of the equation::
     
51
4000
+
21
4000
x +
3
2000
x × 1 +
3
2000
x x = 1 + 1 x + 1 x × 1 + 1 x x + 1 x (1 + x )
    The equation is reduced to :
     
51
4000
+
21
4000
x +
3
2000
x +
3
2000
x x = 1 + 1 x + 1 x + 1 x x + 1 x (1 + x )(1 + x )
    The equation is reduced to :
     
51
4000
+
27
4000
x +
3
2000
x x = 1 + 2 x + 1 x x + 1 x (1 + x )(1 + x )
    Remove a bracket on the right of the equation::
     
51
4000
+
27
4000
x +
3
2000
x x = 1 + 2 x + 1 x x + 1 x × 1(1 + x ) + 1 x
    The equation is reduced to :
     
51
4000
+
27
4000
x +
3
2000
x x = 1 + 2 x + 1 x x + 1 x (1 + x ) + 1 x x
    Remove a bracket on the right of the equation::
     
51
4000
+
27
4000
x +
3
2000
x x = 1 + 2 x + 1 x x + 1 x × 1 + 1 x x
    The equation is reduced to :
     
51
4000
+
27
4000
x +
3
2000
x x = 1 + 2 x + 1 x x + 1 x + 1 x x + 1
    The equation is reduced to :
     
51
4000
+
27
4000
x +
3
2000
x x = 1 + 3 x + 1 x x + 1 x x + 1 x x

    
        x≈-0.797356 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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