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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 12*0.02*325*(1+0.12a)+13*0.019*300*(1-0.1a) = 156 .
    Question type: Equation
    Solution:Original question:
     12 ×
1
50
× 325(1 +
3
25
a ) + 13 ×
19
1000
× 300(1
1
10
a ) = 156
     Left side of the equation = 78(1 +
3
25
a ) +
741
10
(1
1
10
a )
    The equation is transformed into :
     78(1 +
3
25
a ) +
741
10
(1
1
10
a ) = 156
    Remove the bracket on the left of the equation:
     Left side of the equation = 78 × 1 + 78 ×
3
25
a +
741
10
(1
1
10
a )
                                             = 78 +
234
25
a +
741
10
(1
1
10
a )
                                             = 78 +
234
25
a +
741
10
× 1
741
10
×
1
10
a
                                             = 78 +
234
25
a +
741
10
741
100
a
                                             =
1521
10
+
39
20
a
    The equation is transformed into :
     
1521
10
+
39
20
a = 156

    Transposition :
     
39
20
a = 156
1521
10

    Combine the items on the right of the equation:
     
39
20
a =
39
10

    The coefficient of the unknown number is reduced to 1 :
      a =
39
10
÷
39
20
        =
39
10
×
20
39
        = 1 × 2

    We obtained :
      a = 2
    This is the solution of the equation.



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