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    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 846×[（1+0.0435）1-1]+（80+27.78+0.01V）×[（1+0.0435）0.5-1] = 0 .
    Question type: Equation
    Solution:Original question:
     846((1 +
87
2000
) × 1 − 1) + (80 +
1389
50
 +
1
100
 V )((1 +
87
2000
) ×
1
2
 − 1) = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = 846(1 +
87
2000
) × 1 − 846 × 1 + (80 +
1389
50
 +
1
100
 V )((1 +
87
2000
) ×
1
2
 − 1)
                                             = 846(1 +
87
2000
) − 846 + (80 +
1389
50
 +
1
100
 V )((1 +
87
2000
) ×
1
2
 − 1)
                                             = 846 × 1 + 846 ×
87
2000
 − 846 + (80 +
1389
50
 +
1
100
 V )((1 +
87
2000
) ×
1
2
 − 1)
                                             = 846 +
36801
1000
 − 846 + (80 +
1389
50
 +
1
100
 V )((1 +
87
2000
) ×
1
2
 − 1)
                                             =
36801
1000
 + (80 +
1389
50
 +
1
100
 V )((1 +
87
2000
) ×
1
2
 − 1)
                                             =
36801
1000
 + 80((1 +
87
2000
) ×
1
2
 − 1) +
1389
50
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             =
36801
1000
 + 80(1 +
87
2000
) ×
1
2
 − 80 × 1 +
1389
50
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             =
36801
1000
 + 40(1 +
87
2000
) − 80 +
1389
50
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
43199
1000
 + 40(1 +
87
2000
) +
1389
50
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
43199
1000
 + 40 × 1 + 40 ×
87
2000
 +
1389
50
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
43199
1000
 + 40 +
87
50
 +
1389
50
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
1459
1000
 +
1389
50
((1 +
87
2000
) ×
1
2
 − 1) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
1459
1000
 +
1389
50
(1 +
87
2000
) ×
1
2
 −
1389
50
 × 1 +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
1459
1000
 +
1389
100
(1 +
87
2000
) −
1389
50
 +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
29239
1000
 +
1389
100
(1 +
87
2000
) +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
29239
1000
 +
1389
100
 × 1 +
1389
100
 ×
87
2000
 +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
29239
1000
 +
1389
100
 +
120843
200000
 +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
2948957
200000
 +
1
100
 V ((1 +
87
2000
) ×
1
2
 − 1)
                                             = -
2948957
200000
 +
1
100
 V (1 +
87
2000
) ×
1
2
 −
1
100
 V × 1
                                             = -
2948957
200000
 +
1
200
 V (1 +
87
2000
) −
1
100
 V
                                             = -
2948957
200000
 +
1
200
 V × 1 +
1
200
 V ×
87
2000
 −
1
100
 V
                                             = -
2948957
200000
 +
1
200
 V +
87
400000
 V −
1
100
 V
                                             = -
2948957
200000
 −
1913
400000
 V
    The equation is transformed into :
      -
2948957
200000
 −
1913
400000
 V = 0

    Transposition :
      -
1913
400000
 V = 0 +
2948957
200000

    Combine the items on the right of the equation:
      -
1913
400000
 V =
2948957
200000

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
      -
2948957
200000
 =
1913
400000
 V

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
1913
400000
 V = -
2948957
200000

    The coefficient of the unknown number is reduced to 1 :
      V = -
2948957
200000
 ÷
1913
400000
        = -
2948957
200000
 ×
400000
1913
        = - 2948957 ×
2
1913

    We obtained :
      V = -
5897914
1913
    This is the solution of the equation.

    Convert the result to decimal form :
      V = - 3083.07057



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