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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation a(285a+1)(0.25a+1)(0.2a+1)+30(10a+1) = 0 .
    Question type: Equation
    Solution:Original question:
      a (285 a + 1)(
1
4
a + 1)(
1
5
a + 1) + 30(10 a + 1) = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = a × 285 a (
1
4
a + 1)(
1
5
a + 1) + a × 1(
1
4
a + 1)(
1
5
a + 1) + 30(10 a + 1)
                                             = a × 285 a ×
1
4
a (
1
5
a + 1) + a × 285 a × 1(
1
5
a + 1) + a
                                             = a ×
285
4
a a (
1
5
a + 1) + a × 285 a (
1
5
a + 1) + a × 1(
1
4
a + 1)
                                             = a ×
285
4
a a ×
1
5
a + a ×
285
4
a a × 1 + a
                                             = a ×
57
4
a a a + a ×
285
4
a a + a × 285 a
                                             = a ×
57
4
a a a + a ×
285
4
a a + a × 285 a
                                             = a ×
57
4
a a a + a ×
285
4
a a + a × 57 a
                                             = a ×
57
4
a a a + a ×
285
4
a a + a × 57 a
                                             = a ×
57
4
a a a + a ×
285
4
a a + a × 57 a
                                             = a ×
57
4
a a a + a ×
285
4
a a + a × 57 a
                                             = a ×
57
4
a a a + a ×
285
4
a a + a × 57 a
                                             = a ×
57
4
a a a + a ×
285
4
a a + a × 57 a
                                             = a ×
57
4
a a a + a ×
285
4
a a + a × 57 a
                                             = a ×
57
4
a a a + a ×
285
4
a a + a × 57 a
                                             = a ×
57
4
a a a + a ×
285
4
a a + a × 57 a
                                             = a ×
57
4
a a a + a ×
285
4
a a + a × 57 a
    The equation is transformed into :
      a ×
57
4
a a a + a ×
285
4
a a + a × 57 a = 0

    The solution of the equation:
        a1≈-6.371879 , keep 6 decimal places
        a2≈-0.110722 , keep 6 decimal places
    
    There are 2 solution(s).


解程的详细方法请参阅:《方程的解法》



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