Mathematics
         
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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (1÷X)+1÷(X+15) = 1÷4 .
    Question type: Equation
    Solution:Original question:
     (1 ÷ X ) + 1 ÷ ( X + 15) = 1 ÷ 4
     Multiply both sides of the equation by:( X + 15)
     (1 ÷ X )( X + 15) + 1 = 1 ÷ 4 × ( X + 15)
    Remove a bracket on the left of the equation::
     1 ÷ X × ( X + 15) + 1 = 1 ÷ 4 × ( X + 15)
    Remove a bracket on the right of the equation::
     1 ÷ X × ( X + 15) + 1 = 1 ÷ 4 × X + 1 ÷ 4 × 15
    The equation is reduced to :
     1 ÷ X × ( X + 15) + 1 =
1
4
X +
15
4
     Multiply both sides of the equation by: X
     1( X + 15) + 1 X =
1
4
X X +
15
4
X
    Remove a bracket on the left of the equation:
     1 X + 1 × 15 + 1 X =
1
4
X X +
15
4
X
    The equation is reduced to :
     1 X + 15 + 1 X =
1
4
X X +
15
4
X
    The equation is reduced to :
     2 X + 15 =
1
4
X X +
15
4
X

    After the equation is converted into a general formula, it is converted into:
    ( X + 12 )( X - 5 )=0
    From
        X + 12 = 0
        X - 5 = 0

    it is concluded that::
        X1=-12
        X2=5
    
    There are 2 solution(s).


解一元二次方程的详细方法请参阅:《一元二次方程的解法》



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