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    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

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           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (30+7m)*{1.8*(1-0.1m)}+{80-(30+7m)}*{1.5*(1-0.05m)} = 18720 .
    Question type: Equation
    Solution:Original question:
     (30 + 7 m )(
9
5
(1 −
1
10
 m )) + (80 − (30 + 7 m ))(
3
2
(1 −
1
20
 m )) = 18720
    Remove the bracket on the left of the equation:
     Left side of the equation = 30(
9
5
(1 −
1
10
 m )) + 7 m (
9
5
(1 −
1
10
 m )) + (80 − (30 + 7 m ))(
3
2
(1 −
1
20
 m ))
                                             = 30 ×
9
5
(1 −
1
10
 m ) + 7 m (
9
5
(1 −
1
10
 m )) + (80 − (30 + 7 m ))(
3
2
(1 −
1
20
 m ))
                                             = 54(1 −
1
10
 m ) + 7 m (
9
5
(1 −
1
10
 m )) + (80 − (30 + 7 m ))(
3
2
(1 −
1
20
 m ))
                                             = 54 × 1 − 54 ×
1
10
 m + 7 m (
9
5
(1 −
1
10
 m )) + (80 − (30 + 7 m ))(
3
2
(1 −
1
20
 m ))
                                             = 54 −
27
5
 m + 7 m (
9
5
(1 −
1
10
 m )) + (80 − (30 + 7 m ))(
3
2
(1 −
1
20
 m ))
                                             = 54 −
27
5
 m + 7 m ×
9
5
(1 −
1
10
 m ) + (80 − (30 + 7 m ))(
3
2
(1 −
1
20
 m ))
                                             = 54 −
27
5
 m +
63
5
 m (1 −
1
10
 m ) + (80 − (30 + 7 m ))(
3
2
(1 −
1
20
 m ))
                                             = 54 −
27
5
 m +
63
5
 m × 1 −
63
5
 m ×
1
10
 m + (80 − (30 + 7 m ))(
3
2
(1 −
1
20
 m ))
                                             = 54 −
27
5
 m +
63
5
 m −
63
50
 m m + (80 − (30 + 7 m ))(
3
2
(1 −
1
20
 m ))
                                             = 54 +
36
5
 m −
63
50
 m m + (80 − (30 + 7 m ))(
3
2
(1 −
1
20
 m ))
                                             = 54 +
36
5
 m −
63
50
 m m + 80(
3
2
(1 −
1
20
 m )) − (30 + 7 m )(
3
2
(1 −
1
20
 m ))
                                             = 54 +
36
5
 m −
63
50
 m m + 80 ×
3
2
(1 −
1
20
 m ) − (30 + 7 m )(
3
2
(1 −
1
20
 m ))
                                             = 54 +
36
5
 m −
63
50
 m m + 120(1 −
1
20
 m ) − (30 + 7 m )(
3
2
(1 −
1
20
 m ))
                                             = 54 +
36
5
 m −
63
50
 m m + 120 × 1 − 120 ×
1
20
 m − (30 + 7 m )
                                             = 54 +
36
5
 m −
63
50
 m m + 120 − 6 m − (30 + 7 m )(
3
2
(1 −
1
20
 m ))
                                             = 174 +
6
5
 m −
63
50
 m m − (30 + 7 m )(
3
2
(1 −
1
20
 m ))
                                             = 174 +
6
5
 m −
63
50
 m m − 30(
3
2
(1 −
1
20
 m )) − 7 m (
3
2
(1 −
1
20
 m ))
                                             = 174 +
6
5
 m −
63
50
 m m − 30 ×
3
2
(1 −
1
20
 m ) − 7 m (
3
2
(1 −
1
20
 m ))
                                             = 174 +
6
5
 m −
63
50
 m m − 45(1 −
1
20
 m ) − 7 m (
3
2
(1 −
1
20
 m ))
                                             = 174 +
6
5
 m −
63
50
 m m − 45 × 1 + 45 ×
1
20
 m − 7
                                             = 174 +
6
5
 m −
63
50
 m m − 45 +
9
4
 m − 7 m (
3
2
(1 −
1
20
 m ))
                                             = 129 +
69
20
 m −
63
50
 m m − 7 m (
3
2
(1 −
1
20
 m ))
                                             = 129 +
69
20
 m −
63
50
 m m − 7 m ×
3
2
(1 −
1
20
 m )
                                             = 129 +
69
20
 m −
63
50
 m m −
21
2
 m (1 −
1
20
 m )
                                             = 129 +
69
20
 m −
63
50
 m m −
21
2
 m × 1 +
21
2
 m ×
1
20
    This equation has no real solution!


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